How do I create WCF EndPointBehaviors in Code rather than the configuration?

Question

I have the following Xml Configuration ``` ``` I want to implement in C# code rather than using the config. I cannot figure out who to do the EndPoint with webHttp to expose this service as a REST service. ``` ServiceHost serviceHost = new ServiceHost(singletonInstance, "http://localhost:1234/MyServic…

Accepted Answer

Typically, when doing REST with WCF, you can either use the `<webHttp>` behavior in config, or you can use the `WebServiceHost` class (instead of the "plain vanilla" `ServiceHost`). Using the `WebServiceHost` includes all the necessary tweaks and bits and pieces to make the REST stuff work - no more webHttp behavior needed.

Of course, this means, you need a separate `WebServiceHost` (in `System.ServiceModel.Web`), which hosts a service as REST exclusively. This may or may not be what you're looking for:

```
WebServiceHost webServiceHost = 
    new WebServiceHost(singletonInstance, "http://localhost:1234/MyService/xml");

WebHttpBinding webBinding = new WebHttpBinding();
webServiceHost.AddServiceEndpoint(typeof(MyService.IMyService), webBinding, "rest");
```

The other option you have is the add a service endpoint to your regular service host, and just configure the web http behavior on that endpoint - endpoint (and service) behaviors are just regular .NET classes, after all, which you can instantiate, and add to the appropriate `Behaviors` collection (on the service or the individual endpoint):

```
WebHttpBinding restBinding = new WebHttpBinding();

ServiceEndpoint restSEP = 
    serviceHost.AddServiceEndpoint(typeof(MyService.IMyService), 
                                   restBinding, "rest");
restSEP.Behaviors.Add(new WebHttpBehavior());
```

Both ways should bring you to your goal, I hope! (or at least get your closer :-)

How do I create WCF EndPointBehaviors in Code rather than the configuration?

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