Is there a way to unique a map[string]interface{} for golang?

dictionary, go

Solution

There is no built in way to do it, so you need to make a function yourself.

If you want to make a general function, you will have to use `reflect`. If you have a specific map type, then you can make it more easily:

package main

import (
    "fmt"
)

func Unique(m map[string]string) map[string]string {
    n := make(map[string]string, len(m))
    ref := make(map[string]bool, len(m))
    for k, v := range m {
        if _, ok := ref[v]; !ok {
            ref[v] = true
            n[k] = v
        }
    }

    return n
}

func main() {
    input := map[string]string{"a": "green", "0": "red", "b": "green", "1": "blue", "2": "red"}
    unique := Unique(input)
    fmt.Println(unique)
}

Possible output

map[a:green 0:red 1:blue]

Playground

Note

Because maps do not maintain order, you cannot know which keys will be stripped away.

Problem

Just like `array_unique` function for php: ``` $input = array("a" => "green", "red", "b" => "green", "blue", "red"); $result = array_unique($input); print_r($result); ``` Output: ``` Array ( [a] => green [0] => red [1] => blue ) ``` Thx!

Original source