How can I implement a map with different data types as values?
c++, dictionary, polymorphism, stdmap
Solution
You want to use `boost::variant`:
std::map <std::string, boost::variant<typeX, typeY>>
Problem
I want to put two (not more) different data types as values into a map as shown in the following example: ``` typeX A, B, ...; typeY Z, Y, ...; void func (typeX) { ... } void func (typeY) { ... } std::map <std::string, what_to_put_here??> map; map["a"] = A; map["z"] = Z; ... std::vector<std::string> list; // This list will be something like "a", "y", ... for (unsigned int i = 0; i < list.size(); ++i) func( map[list[i]] ) ``` Obviously this doesn't work, as the map will only accept one data type of value. However, when looping over `list`, the call to `func()` should be unambiguous since the type of `map[list[i]]` is known. I want to avoid explicit casting or type checking, i.e. something like this: ``` if (typeid( map[list[i]] ).name() == "typeX") func( map[list[i]] ) else if (typeid( map[list[i]] ).name() == "typeY") func( map[list[i]] ) ``` Is this possible? Again, it will be limited to only two different data types.