How do I get a for loop to work with a comma delimited string?
batch-file, cmd, windows
Solution
You've misunderstood the options.
- `tokens=1` means you only want the first token on each line. You want all of the tokens on the line.
- `eol=,` means you want to interpret a comma as the beginning of an end of line comment. You want to use `delims=,` instead to indicate the comma is the delimiter (instead of the default value of whitespace).
FOR /F is primarily for operating on lines in a file. You're not doing that. You're operating on a single string, so Rubens' answer is closer to what you want:
@ECHO OFF
SET test=1,2,3,4
FOR /D %%F IN (%test%) DO (
ECHO .
ECHO %%F
)
However, in theory, you should be able to say something like:
FOR /F "usebackq delims=, tokens=1-4" %%f IN ('1^,2^,3^,4') DO (
ECHO .
ECHO %%f
ECHO .
ECHO %%g
ECHO .
ECHO %%h
ECHO .
ECHO %%i
)
This works as well, but probably doesn't scale in the way you want. Note that you have to escape the comma in the string using the ^ character, and you have to specify the tokens you want and then use the subsequent variables %g, %h and %i to get them.
Problem
This is my code so far: ``` for /f "tokens=1 eol=," %%f IN ("1,2,3,4") do ( echo . echo %%f ) ``` I'm expecting that to produce: ``` . 1 . 2 . ``` etc... But instead I get: ``` . 1 ``` And that's it. What am I missing?