convert int to float to hex

Question

Using scanf, each number typed in, i would like my program to print out two lines: for example ``` byte order: little-endian > 2 2 0x00000002 2.00 0x40000000 > -2 -2 0xFFFFFFFE -2.00 0xC0000000 ``` I can get it to print out the 2 in hex but i also need a float and of course i cant scanf as one when i need to also scan as an int If i cast as a float when i try to printf i get a zero. If i scan in as a float i get the correct output. I have tried to convert the int to a float but it still comes out as zero. here is my output so far ``` Int - float - hex byte order: little-endian >2 2 0x000002 2.00 00000000 ``` it looks like i am converting to a float fine why wont it print as a hex? if i scan in as a float i get the correct hex representation like the first example. this should be something simple. i do need to scan in as a decimal keep in mind i am running this in cygwin here is what i have so far.. ``` #include #include int main(int argc, char *argv[]) { int HexNu…

Accepted Answer

try this:

```
int i = 2;
float f = (float)i;
printf("%#08X", *( (int*) &f ));
```

[EDIT]

@Corey:

let's parse it from inside out:

```
&  f = address of f = say address 0x5ca1ab1e
(int*)  &f = interpret the address 0x5ca1ab1e as integer pointer
*  ((int*)&f) = get the integer at address 0x5ca1ab1e
```

the following is more concise, but it's hard to remember the C language's operator associativity and operator precedence(i prefer the extra clarity of some added parenthesis and whitespace provides):

```
printf("%#08X", *(int*)&f);
```

convert int to float to hex

Solution

Problem