Initialize array of strings

c, initialization

Solution

This example program illustrates initialization of an array of C strings.

#include <stdio.h>

const char * array[] = {
    "First entry",
    "Second entry",
    "Third entry",
};

#define n_array (sizeof (array) / sizeof (const char *))

int main ()
{
    int i;

    for (i = 0; i < n_array; i++) {
        printf ("%d: %s\n", i, array[i]);
    }
    return 0;
}

It prints out the following:

0: First entry
1: Second entry
2: Third entry

Problem

What is the right way to initialize `char**` ? I get coverity error - Uninitialized pointer read (UNINIT) when trying: ``` char **values = NULL; ``` or ``` char **values = { NULL }; ```

Original source

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