Delete columns from numpy array depending on a condition on a single cell
arrays, numpy, python
Solution
Similar to Juh_, but more expressive, and avoiding some minor unnecessary performance overhead. A grand total of 12 highly pythonic, explicit and unambigious characters. This is really numpy 101; if you are still trying to wrap your head around this, you would do yourself a favor by reading a numpy primer.
import numpy as np
a = np.array([[ 0, 1, 2, 0, 4, 5, 6, 7, 8, 9],
[ 0, 11, 0, 13, 0, 15, 0, 17, 18, 0]])
print a[:,a[1]!=0]
Problem
Above all, sorry for my bad English. I have this array `t`: ``` array([[ 0, 1, 2, 0, 4, 5, 6, 7, 8, 9], [ 0, 11, 0, 13, 0, 15, 0, 17, 18, 0]]) ``` I would like to delete the columns where the value of second line is null. Here, I would like to delete the columns 0, 2, 4, 6 and 9, to obtain this array: ``` array([[ 1, 0, 5, 7, 8 ], [ 11, 13, 15, 17, 18 ]]) ``` I tried with `np.sum()` but didn't succeed.