Android shape border with gradient

android, android-drawable, android-layout, xml-drawable

Solution

try something like this:

<?xml version="1.0" encoding="UTF-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android" >

    <item>
        <shape android:shape="rectangle" >
            <gradient
                android:angle="360"
                android:centerColor="#e95a22"
                android:endColor="#ff00b5"
                android:gradientRadius="360"
                android:startColor="#006386"
                android:type="sweep" />

            <stroke
                android:width="2dp"
                android:color="#ff207d94" />
        </shape>
    </item>
    <item
        android:bottom="2dp"
        android:left="2dp"
        android:right="2dp"
        android:top="2dp">
        <shape android:shape="rectangle" >
            <solid android:color="#fff" />
        </shape>
    </item>

</layer-list>

Problem

I want to create a border for a linearLayout. So I decide to create a shape. I want the border to have a gradient. The following is not doing it. It fills the rectangle and then creates a stroke. I don't want a filled rectangle, just the stroke. And I want to apply the gradient to the stroke. ``` <?xml version="1.0" encoding="utf-8"?> <shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="rectangle" > <gradient android:angle="360" android:centerColor="#e95a22" android:endColor="#ff00b5" android:gradientRadius="360" android:startColor="#006386" android:type="sweep" /> <stroke android:width="2dp" android:color="#ff207d94" /> </shape> ```

Original source

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