PHP glob() to list file that doesn't start with underscore?

php, regex

Solution

This'll do it.

$dir = glob("[!_]*.txt");
foreach ($dir as $filename) {
    echo "$filename size " . filesize($filename) . "<br />";
}

Problem

The standard glob() function usage is like ``` $dir = glob("*.txt"); foreach ($dir as $filename) { echo "$filename size " . filesize($filename) . "\n"; } ``` using * as wildcard, but is there a way to negate it to ignore any file that starts with underscore like _something.txt? I am trying to avoid using preg_match() like ``` $dir = glob("*.txt"); foreach ($dir as $filename) { if (! preg_match("^_+", $filename, $match) { // doesn't show if 1st char is _ echo "$filename size " . filesize($filename) . "\n"; } } ``` but instead use glob()'s own regex to avoid loading unnecessary files in the first place, assuming this will be faster.

Original source