AWK multiple patterns substitution

Question

Using AWK I'd like to process this text: ``` #replace count 12 in in #replace in 77 main() {printf("%d",count+in); } ``` Into: ``` in in ma77() {pr77tf("%d",12+77); } ``` When a '#replace' declaration occurs, only the code below it is affected. I've got: ``` /#replace/ { co=$2; czym=$3 } !/#replace/ { gsub(co,czym); print } ``` However I'm getting only ``` in in ma77() {pr77tf("%d",count+77); } ``` in return. As you can see only the second gsub works. Is there a simple way to remeber all the substitutions?

Accepted Answer

You just need to use an array to store the substitutions:

```
$ awk '/#replace/{a[$2]=$3;next}{for(k in a)gsub(k,a[k])}1' file
in in
ma77()
{pr77tf("%d",12+77);
}
```

AWK multiple patterns substitution

Solution

Problem