python - specifically handle file exists exception
exception, ioerror, python
Solution
According to the code `print ...`, it seems like you're using Python 2.x. `FileExistsError` was added in Python 3.3; You can't use `FileExistsError`.
Use `errno.EEXIST`:
import os
import errno
try:
os.mkdir(folderPath)
except OSError as e:
if e.errno == errno.EEXIST:
print('Directory not created.')
else:
raise
Problem
I have come across examples in this forum where a specific error around files and directories is handled by testing the `errno` value in `OSError` (or `IOError` these days ?). For example, some discussion here - Python's "open()" throws different errors for "file not found" - how to handle both exceptions?. But, I think, that is not the right way. After all, a `FileExistsError` exists specifically to avoid having to worry about `errno`. The following attempt didn't work as I get an error for the token `FileExistsError`. ``` try: os.mkdir(folderPath) except FileExistsError: print 'Directory not created.' ``` How do you check for this and similar other errors specifically ?