Haskell String-> Int Type Conversion
haskell
Solution
If you know that the string is a valid integer, or you don't mind it blowing up if that's not the case, `read` will work. If you are unfamiliar with Haskell's typeclasses, just know that you might have to tell Haskell what type you want to read it as:
main :: IO ()
main = do
let x = read "271" :: Integer
print x
You don't always have to do this, if Haskell has some other way of knowing what type you want, like if you proceed to do arithmetic with it.
If you don't know for sure that the string is a valid number, recent versions of base (not sure since when) include a function `readMaybe` that will safely return `Nothing` if it is not a readable integer.
Problem
I'm taking my first few steps in Haskell, and I'm trying to convert a string to an integer, but I'm not managing. I've looked at similar questions and I'm still not sure. All I want to do is convert, e.g. `'6'` or `"271"` to integers, that is, `6` or `271` respectively. How do I do this? The analogue would be that in Python, I could do this easily: e.g.`int("2723")` would get the job done.