How can I read a standard openssl rsa private key with PyCrypto and decrypt with it
cryptography, encryption, pycrypto, rsa, x509
Solution
There is no mistake. The private key is encoded in a password-protected PKCS#8 structure (inside a PEM envelope) and that is not understood by the current version of PyCrypto (2.6).
Support for PKCS#8 is available on the current development branch of the library though.
EDIT: PKCS#8, not PKCS#7
Problem
I generated a private key with: ``` openssl req -x509 -out anytime-pub.der -outform der -new -newkey rsa:2048 -keyout anytime.pem -days 3650 ``` In my old code, I use M2Crypto load the key file to decrypt something, and it works. ``` from M2Crypto import RSA ServerRSA = RSA.load_key('keys/anytime.pem', passwd) key = ServerRSA.private_decrypt(b64decode(cipher),1) ``` but when i use pycrypto to do the same thing, it occurs error below: ``` >>> from Crypto.PublicKey import RSA >>> key = RSA.importKey(open('keys/anytime.pem', 'r')) Traceback (most recent call last): File "<stdin>", line 1, in <module> File "/Users/xyzkizer/Projects/AnytimeBackend/env/lib/python2.7/site-packages/Crypto/PublicKey/RSA.py", line 641, in importKey raise ValueError("PEM encryption format not supported.") ValueError: PEM encryption format not supported. ``` Can anybody tell me what's my mistake? Thank you!