Displaying a cvMatrix containing complex numbers (CV_64FC2)

c++, numpy, opencv, python

Solution

There is a dft example in OpenCV 2.0 code, which I am also studying right now. Here is a copy paste for you that might give you an idea. As you can see, it uses cvSplit to spilit to real and imaginary components. Hope that helps:

im = cvLoadImage( filename, CV_LOAD_IMAGE_GRAYSCALE );
if( !im )
    return -1;

realInput = cvCreateImage( cvGetSize(im), IPL_DEPTH_64F, 1);
imaginaryInput = cvCreateImage( cvGetSize(im), IPL_DEPTH_64F, 1);
complexInput = cvCreateImage( cvGetSize(im), IPL_DEPTH_64F, 2);

cvScale(im, realInput, 1.0, 0.0);
cvZero(imaginaryInput);
cvMerge(realInput, imaginaryInput, NULL, NULL, complexInput);

dft_M = cvGetOptimalDFTSize( im->height - 1 );
dft_N = cvGetOptimalDFTSize( im->width - 1 );

dft_A = cvCreateMat( dft_M, dft_N, CV_64FC2 );
image_Re = cvCreateImage( cvSize(dft_N, dft_M), IPL_DEPTH_64F, 1);
image_Im = cvCreateImage( cvSize(dft_N, dft_M), IPL_DEPTH_64F, 1);

// copy A to dft_A and pad dft_A with zeros
cvGetSubRect( dft_A, &tmp, cvRect(0,0, im->width, im->height));
cvCopy( complexInput, &tmp, NULL );
if( dft_A->cols > im->width )
{
    cvGetSubRect( dft_A, &tmp, cvRect(im->width,0, dft_A->cols - im->width, im->height));
    cvZero( &tmp );
}

// no need to pad bottom part of dft_A with zeros because of
// use nonzero_rows parameter in cvDFT() call below

cvDFT( dft_A, dft_A, CV_DXT_FORWARD, complexInput->height );

cvNamedWindow("win", 0);
cvNamedWindow("magnitude", 0);
cvShowImage("win", im);

// Split Fourier in real and imaginary parts
cvSplit( dft_A, image_Re, image_Im, 0, 0 );

// Compute the magnitude of the spectrum Mag = sqrt(Re^2 + Im^2)
cvPow( image_Re, image_Re, 2.0);
cvPow( image_Im, image_Im, 2.0);
cvAdd( image_Re, image_Im, image_Re, NULL);
cvPow( image_Re, image_Re, 0.5 );

// Compute log(1 + Mag)
cvAddS( image_Re, cvScalarAll(1.0), image_Re, NULL ); // 1 + Mag
cvLog( image_Re, image_Re ); // log(1 + Mag)

Problem

I'm new to OpenCV, and I would like to compare the results of a python program with my calculations in OpenCV. My matrix contains complex numbers since its the result of a cvDFT. Python handles complex numbers well and displays it with scientific notation. My C++ program is not effective when trying to use std::cout. I tried to store my numbers array in a std::complex[] instead of a double[] but it is not compiling. Here is my code, and its result : ``` CvMat *dft_A; dft_A = cvCreateMat(5, 5, CV_64FC2); // complex matrix double a[] = { 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4 }; dft_A->data.db = a; std::cout << "before : " << a[0] << std::endl; cvDFT( dft_A, dft_A, CV_DXT_FORWARD); // DFT ! std::cout << "after : " << a[0] << std::endl; >> before : 0 ``` Here is the same in python, with the output : ``` >>> a = np.mgrid[:5, :5][0] >>> a array([[0, 0, 0, 0, 0], [1, 1, 1, 1, 1], [2, 2, 2, 2, 2], [3, 3, 3, 3, 3], [4, 4, 4, 4, 4]]) >>> np.fft.fft2(a) array([[ 50.0 +0.j , 0.0 +0.j , 0.0 +0.j , 0.0 +0.j , 0.0 +0.j ], [-12.5+17.20477401j, 0.0 +0.j , 0.0 +0.j , 0.0 +0.j , 0.0 +0.j ], [-12.5 +4.0614962j , 0.0 +0.j , 0.0 +0.j , 0.0 +0.j , 0.0 +0.j ], [-12.5 -4.0614962j , 0.0 +0.j , 0.0 +0.j , 0.0 +0.j , 0.0 +0.j ], [-12.5-17.20477401j, 0.0 +0.j , 0.0 +0.j , 0.0 +0.j , 0.0 +0.j ]]) >>> ``` The problem is obviously coming from the second cout which is inefficient with the type of date (CV_64FC2 for complex number). My question is : how can I dump the result so I can check that my python code is doing the same as my cpp/opencv code ? Thanks !

Original source