PHP: Return string between two characters
keyword, php, regex, replace, string
Solution
<?php
// keywords are between *
$str = "PHP is the *best*, its the *most popular* and *I* love it.";
if(preg_match_all('/\*(.*?)\*/',$str,$match)) {
var_dump($match[1]);
}
?>
Output:
array(3) {
[0]=>
string(4) "best"
[1]=>
string(12) "most popular"
[2]=>
string(1) "I"
}
Problem
I am wanting to use "keywords" within a large string. These keywords start and end using my_keyword and are user defined. How, within a large string, can I search and find what is between the two * characters and return each instance? The reason it might change it, that parts of the keywords can be user defined, such as page_date_Y which might show the year in which the page was created. So, again, I just need to do a search and return what is between those * characters. Is this possible, or is there a better way of doing this if I don't know the "keyword" length or what i might be?