AWK script to print line with the largest number of fields
awk, gawk, linux, unix
Solution
awk '{if (NF > max) {max = NF; line=$0}} END{print line}' twister.txt
Problem
The script below displays the largest number of fields in twister.txt. ``` awk '{if (NF > max) max = NF} END{print max}' twister.txt ``` My question is, How do you display the line itself, which has the largest number of fields in twister.txt.