Configure Windows to use 32-bit JRE instead of 64-bit JRE

In my system, I have 64-bit Java 1.7 installed here: `C:\Program Files\Java\jdk1.7.0_40` And I have 32-bit Java 1.7 installed here: `C:\Program Files (x86)\Java\jdk1.7.0_02` When I issue `java -version` command in CMD, it shows me this: ``` C:\Users\Meraman>java -version java version "1.7.0_40" Java(TM) SE Runtime Environment (build 1.7.0_40-b43) Java HotSpot(TM) 64-Bit Server VM (build 24.0-b56, mixed mode) ``` I want to change Java version to 32-bit. I have tried the following: Removed path to 64-bit installation from `path` variable, but still CMD shows same output for `java -version` command. I have specified only 32-bit installation path in `path` variable, but still CMD shows same output for `java -version` command. Then added `JAVA_HOME` variable with value `C:\Program Files (x86)\Java\jdk1.7.0_02`, but still CMD shows same output. In Java Control Panel->Java->Java Runtime Environment Settings->User, I have completed wizard to find 32-bit Java and enabled that only, with disabling 64-bit installation, but still CMD shows same output. Please help me on this, I want to change Java to 32-bit without un-installing 64-bit. More info: I have restarted CMD after every changes to path or Java Control Panel. I have `path` and `JAVA_HOME` as system variables only, no any such user variables. EDIT I have removed all java paths setting in path variable, removed JAVA_HOME variable, and still CMD shows 64-bit. ``` C:\Users\Meraman>echo %PATH% C:\oraclexe\app\oracle\product\10.2.0\server\bin;C:\Python33\;C:\Program Files ( x86)\AMD APP\bin\x86_64;C:\Program Files (x86)\AMD APP\bin\x86;C:\Windows\system 32;C:\Windows;C:\Windows\System32\Wbem;C:\Windows\System32\WindowsPowerShell\v1. 0\;C:\Program Files (x86)\ATI Technologies\ATI.ACE\Core-Static;C:\Program Files (x86)\Microsoft SQL Server\80\Tools\Binn\;C:\Program Files (x86)\Microsoft SQL S erver\90\Tools\binn\;C:\Program Files (x86)\Microsoft SQL Server\90\DTS\Binn\;C: \Program Files (x86)\Microsoft SQL Server\90\Tools\Binn\VSShell\Common7\IDE\;C:\ Program Files (x86)\Microsoft Visual Studio 8\Common7\IDE\PrivateAssemblies\; C:\Users\Meraman>javac -version 'javac' is not recognized as an internal or external command, operable program or batch file. C:\Users\Meraman>java -version java version "1.7.0_40" Java(TM) SE Runtime Environment (build 1.7.0_40-b43) Java HotSpot(TM) 64-Bit Server VM (build 24.0-b56, mixed mode) C:\Users\Meraman>echo %JAVA_HOME% %JAVA_HOME% C:\Users\Meraman> ``` EDIT - This worked: Setting very first path in path variable to 32-bit java worked. Here is output from CMD: ``` C:\Users\Meraman>echo %PATH% C:\Program Files (x86)\Java\jdk1.7.0_02\bin;C:\oraclexe\app\oracle\product\10.2. 0\server\bin;C:\Python33\;C:\Program Files (x86)\AMD APP\bin\x86_64;C:\Program F iles (x86)\AMD APP\bin\x86;C:\Windows\system32;C:\Windows;C:\Windows\System32\Wb em;C:\Windows\System32\WindowsPowerShell\v1.0\;C:\Program Files (x86)\ATI Techno logies\ATI.ACE\Core-Static;C:\Program Files (x86)\Microsoft SQL Server\80\Tools\ Binn\;C:\Program Files (x86)\Microsoft SQL Server\90\Tools\binn\;C:\Program File s (x86)\Microsoft SQL Server\90\DTS\Binn\;C:\Program Files (x86)\Microsoft SQL S erver\90\Tools\Binn\VSShell\Common7\IDE\;C:\Program Files (x86)\Microsoft Visual Studio 8\Common7\IDE\PrivateAssemblies\; C:\Users\Meraman>javac -version javac 1.7.0_02 C:\Users\Meraman>java -version java version "1.7.0_02" Java(TM) SE Runtime Environment (build 1.7.0_02-b13) Java HotSpot(TM) Client VM (build 22.0-b10, mixed mode, sharing) C:\Users\Meraman>echo %JAVA_HOME% %JAVA_HOME% C:\Users\Meraman>where java C:\Program Files (x86)\Java\jdk1.7.0_02\bin\java.exe C:\Windows\System32\java.exe C:\Users\Meraman> ```