How to reference a ModelView in flask-admin

flask, flask-admin, python

Solution

OK I figured it out after reading the source code for ModelView.

First, make sure that endpoints are named (it's possible to do it without named endpoints, but this makes the code much clearer):

from flask.ext.admin.contrib.sqla import ModelView
from models import db, User, Role

admin = Admin(app, name="Boost Admin")

admin.add_view(ModelView(User,db.session,category="model", endpoint="model_view_user"))
admin.add_view(ModelView(Role,db.session,category="model", endpoint="model_view_role"))

...now in the template, you can reference the basic model view as follows:

URL for User model default view is: {{model_view_user.index_view}} 
URL for Role model default view is: {{model_view_role.index_view}}

The `index_view` function is defined here, and implements the default view for a flask admin ModelView.

Problem

What's the right way to get the URL for a flask-admin `ModelView`? Here's a very simple example: my_admin_view.py ``` from flask.ext.admin.contrib.sqla import ModelView from common.flask_app import app from models import db, User, Role admin = Admin(app, name="Boost Admin") admin.add_view(ModelView(User, db.session, category="model")) admin.add_view(ModelView(Role, db.session, category="model")) ``` my_admin_template.html ``` ... <p>Check out my user admin link:</p> <a href="{{ url_for('modelview.user') }}">User view link</a> {# ______________ what argument to pass in here?? #} ... ``` What's the correct argument to pass to `url_for(...)`? I've tried `modelview.user`, `my_admin_view.modelview.user`, etc. None of them seem to resolve correctly, and I'd like to avoid hardcoding the link. thanks!

Original source