Percentage Based Probability
c#, percentage, probability
Solution
This is very easy to check for yourself:
Random rand = new Random();
int yes = 0;
const int iterations = 10000000;
for (int i = 0; i < iterations; i++)
{
if (rand.Next(1, 101) <= 25)
{
yes++;
}
}
Console.WriteLine((float)yes/iterations);
the result:
0.2497914
The conslusion: Yes, yes it is.
Edit: Just for fun, the LINQy version:
Random rand = new Random();
const int iterations = 10000000;
int sum = Enumerable.Range(1, iterations)
.Count(i => rand.Next(1, 101) <= 25);
Console.WriteLine(sum / (float)iterations);
Problem
I have this code snippet: ``` Random rand = new Random(); int chance = rand.Next(1, 101); if (chance <= 25) // probability of 25% { Console.WriteLine("You win"); } else { Console.WriteLine("You lose"); } ``` My question is, does it really calculate a 25% probability for winning here? Is the chance of winning for the player here is really 25%? Edit: I just wrote this: ``` double total = 0; double prob = 0; Random rnd = new Random(); for (int i = 0; i < 100; i++) { double chance = rnd.Next(1, 101); if (chance <= 25) prob++; total++; } Console.WriteLine(prob / total); Console.ReadKey(); ``` And it's highly inaccurate. It goes from about 0.15 to 0.3. But when I do more checks (change from (i < 100) to (i < 10000)) it's much more accurate. Why is this? Why aren't 100 checks enough for it to be accurate?