UnicodeDecodeError with xlwt
python, python-2.7, xlwt
Solution
Have you tried encoding latin-1 for workbook??
from xlwt import Workbook
hoja = Workbook(encoding='latin-1')
Problem
I'm using python with xlwt and have a problem My code: ``` tickets = cursor.fetchall () largo = len(tickets) cursor.close () conn.close () row = 4 for t in tickets: hoja.write(row, 1, t[0]) hoja.write(row, 2, epoch2fecha(t[1])) hoja.write(row, 3, epoch2fecha(t[12])) hoja.write(row, 6, t[10]) hoja.write(row, 7, t[9]) hoja.write(row, 8, t[6]) hoja.write(row, 9, t[3]) row += 1 if(row == largo+1): break libro.save('Informe.xls') ``` Error: ``` libro.save('informe.xlsx') File "build/bdist.linux-x86_64/egg/xlwt/Workbook.py", line 662, in save File "build/bdist.linux-x86_64/egg/xlwt/Workbook.py", line 637, in get_biff_data File "build/bdist.linux-x86_64/egg/xlwt/Workbook.py", line 599, in __sst_rec File "build/bdist.linux-x86_64/egg/xlwt/BIFFRecords.py", line 76, in get_biff_record File "build/bdist.linux-x86_64/egg/xlwt/BIFFRecords.py", line 91, in _add_to_sst File "build/bdist.linux-x86_64/egg/xlwt/UnicodeUtils.py", line 50, in upack2 UnicodeDecodeError: 'ascii' codec can't decode byte 0xf3 in position 6: ordinal not in range(128) ```