Django CreateView customise form default field based on url parameter
create-view, django, django-forms, python
Solution
You can use the pattern described in the documentation for adding request.user - it's the same principle. Remove `env` from the fields list, then define `form_valid()`:
class EnvhostsCreate(CreateView):
model = Capacity.models.Envhosts
fields = ['hostname', 'count']
template_name_suffix = '_create_form'
def form_valid(self, form):
form.instance.env = Envhosts.objects.get(pk=self.kwargs['envid'])
return super(EnvhostsCreate, self).form_valid(form)
Problem
file: Capacity/models.py ``` class Env(models.Model): name = models.CharField(max_length=50) def get_absolute_url(self): return reverse('index') class Envhosts(models.Model): env = models.ForeignKey(Env) hostname = models.CharField(max_length=50) count = models.IntegerField() class Meta: unique_together = ("env","hostname") def get_absolute_url(self): return reverse('index') ``` file: Capacity/views.py ``` class EnvhostsCreate(CreateView): model = Capacity.models.Envhosts fields=['env','hostname','count'] template_name_suffix = '_create_form' ``` file Capacity/urls.py: ``` urlpatterns = patterns(........ url(r'^createhosts/(?P<envid>\d+)/$',EnvhostsCreate.as_view(),name='envhosts_create')) ``` So now, when i open this form: `/Capacity/createhosts/3/` (where 3 is my env id) It shows an option of env objects as a drop down list based on the number of object of Env. But i want it to take the env on its own based on the env id ('3' in this case) I know i have to override some method in class EnvhostsCreate(CreateView). But i m unable to figure out which method and how to take the env based on the part after `/createhosts/`