Python check for NoneType not working

if-statement, nonetype, python

Solution

In Python, `|` is a bitwise or. You want to use a logical or here:

if (cts is None) or (len(cts) == 0):
    return

Problem

I'm trying to check whether an object has a None type before checking it's length. For this, I've done an if statement with an or operator: ``` if (cts is None) | (len(cts) == 0): return ``` As far as I can tell, the object `cts` will be checked if it's None, and if it is, the length check won't run. However, the following error happens if `cts` is None: `TypeError: object of type 'NoneType' has no len()` Does python check both expressions in an if statement, even if the first is true?

Original source