Array Index Out of Bounds For Loop Print Contents ArrayList

Question

``` // ArrayList import java.io.*; import java.util.*; public class ArrayListProgram { public static void main (String [] args) { Integer obj1 = new Integer (97); String obj2 = "Lama"; CD obj3 = new CD("BlahBlah", "Justin Bieber", 25.0, 13); ArrayList objects = new ArrayList(); objects.add(obj1); objects.add(obj2); objects.add(obj3); System.out.println("Contents of ArrayList: "+objects); System.out.println("Size of ArrayList: "+objects.size()); BodySystems bodyobj1 = new BodySystems("endocrine"); BodySystems bodyobj2 = new BodySystems("integumentary"); BodySystems bodyobj3 = new BodySystems("cardiovascular"); objects.add(1, bodyobj1); objects.add(3, bodyobj2); objects.add(5, bodyobj3); System.out.println(); System.out.println(); int i; for(i=0; i<objects.size(); i++); { System.out.println(objects.get(i)); } ``` } } The for loop is attempting to print the contents of the array list using the size() method. How can I stop getting an ArrayIndexOutOfBounds error? I have indexes 0-5 in my…

Accepted Answer

The problem is your stray semi-colon at the end of the `for` loop:

```
for(i=0; i<objects.size(); i++); // Spot the semi-colon here
{
    System.out.println(objects.get(i));
}
```

That means your code is effectively:

```
for(i=0; i<objects.size(); i++)
{
}
System.out.println(objects.get(i));
```

That's now more obviously wrong, because it's using `i` after it's reached the end of the loop.

You could spot this at compile-time if you used the more idiomatic approach of declaring `i` inside the `for` statement:

```
for (int i = 0; i < objects.size(); i++)
```

... at that point `i` would be out of scope in the call to `System.out.println`, so you'd get a compile-time error.

Array Index Out of Bounds For Loop Print Contents ArrayList

Solution

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