Easy way to get the keys in a map in alphabetical order

dictionary, go, sorting

Solution

You are sorting an array of strings using StringVector. To minimize overhead, you could sort an array of strings.

package main

import (
    "fmt"
    "sort"
)

func main() {
    m := map[string]string{"b": "15", "z": "123123", "x": "sdf", "a": "12"}
    mk := make([]string, len(m))
    i := 0
    for k, _ := range m {
        mk[i] = k
        i++
    }
    sort.Strings(mk)
    fmt.Println(mk)
}

Output:

[a b x z]

Problem

In Go, what's the easiest way to get the keys in a map sorted alphabetically? This is the shortest way I can do it: ``` package main import "container/vector" import "fmt" import "sort" func main() { m := map[string]string {"b":"15", "z":"123123", "x":"sdf", "a":"12"} var keys vector.StringVector; for k,_ := range ( m ) { keys.Push(k) } sort.Sort( &keys ) fmt.Printf("%v\n", keys) } ```

Original source