Fill an array with random numbers

arrays, java

Solution

You need to add logic to assign random values to double[] array using randomFill method.

Change

 public static double[] list(){
    anArray = new double[10];   
    return anArray;
 }

To

 public static double[] list() {
    anArray = new double[10];
    for(int i=0;i<anArray.length;i++)
    {
        anArray[i] = randomFill();
    }
    return anArray;
}

Then you can call methods, including list() and print() in main method to generate random double values and print the double[] array in console.

 public static void main(String args[]) {

list();
print();
 }

One result is as follows:

-2.89783865E8 
1.605018025E9 
-1.55668528E9 
-1.589135498E9 
-6.33159518E8 
-1.038278095E9 
-4.2632203E8 
1.310182951E9 
1.350639892E9 
6.7543543E7

Problem

I need to create an array using a constructor, add a method to print the array as a sequence and a method to fill the array with random numbers of the type double. Here's what I've done so far: ``` import java.util.Random; public class NumberList { private static double[] anArray; public static double[] list() { return new double[10]; } public static void print(){ System.out.println(String.join(" ", anArray); } public static double randomFill() { return (new Random()).nextInt(); } public static void main(String args[]) { // TODO } } ``` I'm struggling to figure out how to fill the array with the random numbers I have generated in the randomFill method. Thanks!

Original source