Remove last char from result of a match regex

I'm trying to extract a part of html in a jmeter test. I need to extract just a part from a `<script src=""` tag. full script src: `<script src="/Paginas/Inicializacao/AguardarAcao.aspx?_TSM_HiddenField_=ctl00_ToolkitScriptManager1_HiddenField&amp;_TSM_CombinedScripts_=%3b%3bAjaxControlToolkit%2c+Version%3d1.0.11119.38311%2c+Culture%3dneutral%2c+PublicKeyToken%3d28f01b0e84b6d53e%3apt-BR%3adf9c6e46-ef8c-4a3d-89af-f80adf22e9c2%3a865923e8%3a411fea1c%3ae7c87f07%3a91bd373d%3a1d58b08c%3a8e72a662%3aacd642d2%3a596d588c%3a77c58d20%3a14b56adc%3a269a19ae" type="text/javascript"></script>` and I need just: `%3b%3bAjaxControlToolkit%2c+Version%3d1.0.11119.38311%2c+Culture%3dneutral%2c+PublicKeyToken%3d28f01b0e84b6d53e%3apt-BR%3adf9c6e46-ef8c-4a3d-89af-f80adf22e9c2%3a865923e8%3a411fea1c%3ae7c87f07%3a91bd373d%3a1d58b08c%3a8e72a662%3aacd642d2%3a596d588c%3a77c58d20%3a14b56adc%3a269a19ae` Right now I created this regex: ``` %3b.*" ``` that matches: ``` %3b%3bAjaxControlToolkit%2c+Version%3d1.0.11119.38311%2c+Culture%3dneutral%2c+PublicKeyToken%3d28f01b0e84b6d53e%3apt-BR%3adf9c6e46-ef8c-4a3d-89af-f80adf22e9c2%3a865923e8%3a411fea1c%3ae7c87f07%3a91bd373d%3a1d58b08c%3a8e72a662%3aacd642d2%3a596d588c%3a77c58d20%3a14b56adc%3a269a19ae" ``` But I don't want the last two chars (one white space) and the `"`. How to remove this last two chars?