python: regular expression search pattern for binary files (half a byte)

Question

I am using the following regular expression pattern for searching 0xDEAD4FAD in a binary file: ``` my_pattern = re.compile(b"\xDE\xAD\x4F\xAD") ``` but how do I generalize the search pattern for searching 0xDEAD4xxx? can't seem to cut through half a byte

Accepted Answer

Regular expressions do allow searching over ranges. Thus, to find a byte whose the first nibble is "4" use:

```
pattern = re.compile(b"[\x40-\x4F]")
```

The following test shows that it produces the desired output:

```
>>> for byte in ('\x3f', '\x40', '\x42', '\x4f', '\x50'): print bool(pattern.search(byte))
... 
False
True
True
True
False
```

To answer your specific question about searching for 0xDEAD4xxx, use:

```
my_pattern = re.compile(b"\xDE\xAD[\x40-\x4F].")
```

python: regular expression search pattern for binary files (half a byte)

Solution

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