how to extract matched string in scala?

Question

I want to extract sub-strings from a string by using regular expressions in Scala. For example, the string ``` line = "[129]: (29) -> (1): Rumor" ``` I want extract three numbers and last sub-string (`"Rumor"`) from line. How do I implement it in scala? Update: Thanks @Shyamendra Solanki, it works now. But I have another problem. When I read a line from a file and parse this line using your regex, eclipse reports weird error (I have no idea what's wrong). But if I do not use it, no error is reported. ``` val pattern = """$$(\d+)$$:\s$(\d+)$\s\W\W\s$(\d)$:\s(\w+)""".r // define regex for(line: String <- Source.fromFile(f1).getLines()){ val pattern(clock, from, to, msg) = line println(clock+", "+ from+", "+to+", msg") } ``` error: ``` Exception in thread "AWT-EventQueue-0" scala.MatchError: [1]: (1) <- (0): Init([LNode;@1f18e146,Full@1a6dca9d) (of class java.lang.String) at TwoNodeQuery$$anon$1$$anonfun$1$$anonfun$apply$mcV$sp$2.apply(Analysis.scala:74) at TwoNodeQuery$$anon$1$$anon…

Accepted Answer

```
val re = """$$(\d+)$$:\s$(\d+)$\s\W\W\s$(\d)$:\s(\S+)""".r // define regex 
val s = "[129]: (29) -> (1): Rumor"   // line to match
val re(n1, n2, n3, s1) = s            // pattern match and extract values
(n1.toInt, n2.toInt, n3.toInt, s1)    // convert to expected types
```

how to extract matched string in scala?

Solution

Problem