What is '$$' in the bash shell?

Question

I'm beginner at bash shell programming. Can you tell me about '$$' symbols in the bash shell? If I try the following ``` #> echo $$ ``` it prints ``` #>18756 ``` Can you tell me what this symbol is used for and when?

Accepted Answer

It's the process id of the bash process itself.

You might use it to track your process over its life - use `ps -p` to see if it's still running, send it a signal using `kill` (to pause the process for example), change its priority with `renice`, and so on.

Process ids are often written to log files, especially when multiple instances of a script run at once, to help track performance or diagnose problems.

Here's the bash documentation outlining special parameters.

`BASHPID`, mentioned by ghostdog74, was added at version 4.0. Here's an example from Mendel Cooper's Advanced Bash-Scripting Guide that shows the difference between `$$` and `$BASHPID`:

```
#!/bin/bash4

echo "\$\$ outside of subshell = $$" # 9602
echo "\$BASH_SUBSHELL outside of subshell = $BASH_SUBSHELL" # 0
echo "\$BASHPID outside of subshell = $BASHPID" # 9602
echo

( echo "\$\$ inside of subshell = $$" # 9602
echo "\$BASH_SUBSHELL inside of subshell = $BASH_SUBSHELL" # 1
echo "\$BASHPID inside of subshell = $BASHPID" ) # 9603
# Note that $$ returns PID of parent process.
```

What is '$$' in the bash shell?

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