ImageCreateFromString and getimagesize in PHP

image-processing, php

Solution

I suggest you follow this approach:

// if you need the image type
$type = exif_imagetype($url);

// if you need the image mime type
$type = image_type_to_mime_type(exif_imagetype($url));

// if you need the image extension associated with the mime type
$type = image_type_to_extension(exif_imagetype($url));

// if you don't care about the image type ignore all the above code
$image = ImageCreateFromString(file_get_contents($url));

echo ImageSX($image); // width
echo ImageSY($image); // height

Using `exif_imagetype()` is a lot faster than `getimagesize()`, the same goes for `ImageSX()` / `ImageSY()`, plus they don't return arrays and can also return the correct image dimension after the image has been resized or cropped for instance.

Also, using `getimagesize()` on URLs isn't good because it'll consume much more bandwidth than the alternative `exif_imagetype()`, from the PHP Manual:

When a correct signature is found, the appropriate constant value will be returned otherwise the return value is FALSE. The return value is the same value that `getimagesize()` returns in index 2 but `exif_imagetype()` is much faster.

That's because `exif_imagetype()` will only read the first few bytes of data.

Problem

Currently if a user POST/uploads a photo to my PHP script I start out with some code like this ``` getimagesize($_FILES['picture1']['tmp_name']); ``` I then do a LOT more stuff to it but I am trying to also be able to get a photo from a URL and process it with my other existing code if I can. SO I am wanting to know, I f I use something like this ``` $image = ImageCreateFromString(file_get_contents($url)); ``` Would I be able to then run getimagesize() on my $image variable? UPDATE I just tried this... ``` $url = 'http://a0.twimg.com/a/1262802780/images/twitter_logo_header.png'; $image = imagecreatefromstring(file_get_contents($url)); $imageinfo = getimagesize($image); print_r($imageinfo); ``` But it didnt work, gave this. ``` Warning: getimagesize(Resource id #4) [function.getimagesize]: failed to open stream: No such file or directory in ``` Any idea how I can do this or something similar to get the result I am after?

Original source