How to get to a particular page in dbpedia using sparql query?

dbpedia, rdf, semantic-web, sparql

Solution

You don't want properties of a page, you want propreties of aresource. In this case, the resource is `<http://dbpedia.org/resource/Ashok_Gehlot>`. RDF is a graph based data representation, and a SPARQL query is a graph based query language. You're looking for an edge of the graph whose source is `<http://dbpedia.org/resource/Ashok_Gehlot>`, whose edge label is `owl:birthdate` (which doesn't make sense, but that's a different issue), and you want to retrieve the other end of the edge and bind its value to the variable `?z`. Thus, your query would be:

select ?z where { 
  <http://dbpedia.org/resource/Ashok_Gehlot> owl:birthdate ?z
}

SPARQL results

Of course, that query has no results, because the resource has no property `owl:birthdate`. If you browse the data that you see at Ashok Gehlot, you'll notice that there are:

- dbpedia-owl:birthDate 1951-05-03 (xsd:date)

- dbpprop:birthDate 3 (xsd:integer)

- dbpprop:dateOfBirth 1951 (xsd:integer)

The dbpedia-owl data is much cleaner than the dbpprop data, so you should use it. Also noting that the prefix `dbpedia:` abbreviates `<http://dbpedia.org/resource/>`, your query should be:

select ?birthDate where { 
  dbpedia:Ashok_Gehlot dbpedia-owl:birthDate ?birthDate
}

SPARQL results

--------------
| birthDate  |
|============|
| 1951-05-03 |
--------------

If, for some reason, it really is important to have a query that's more in the shape of your original attempt, you could use the following. The pattern `?x owl:sameAs? dbpedia:Ashok_Gehlot` means that `?x` will be bound to things that are zero or one step away from `dbpedia:Ashok_Gehlot` by the property `owl:sameAs`. For the zero step case, `?x` is just `dbpedia:Ashok_Gehlot`, which is what you want. For the one case, `?x` will be anything that is `owl:sameAs dbpedia:Ashok_Gehlot`, which should also be OK.

select ?birthDate where { 
  ?x owl:sameAs? dbpedia:Ashok_Gehlot .
  ?x dbpedia-owl:birthDate ?birthDate .
}

SPARQL results

Problem

Original source