Download zip InputStream Struts2 Java
inputstream, java, struts2, zip
Solution
The parameter `<param name="inputName">inputStream</param>` tells Struts2 from where to get the raw bytes that will be sent to the client. In your case, you want to send the zipped bytes. Instead, you are setting `inputStream=ZipInputStream` , which is a stream that takes a zipped source - to unzip sit. You don't want that, you want to send the raw zipped bytes.
REplace then
inputStream = new ZipInputStream(new ByteArrayInputStream(baos.toByteArray()))
by
inputStream = new ByteArrayInputStream(baos.toByteArray())
and it should work
Problem
First, sorry for english. I wanna know if you can help me to resolve this problem. What I'm trying is to download a zip that I have create from multiple byte[] using Struts2 and stream result. I use ZipOutputStream and I have managed to create a File from it and read and download it using FileInputStream, but my problem is that I don't wan't to create a File. I just wanna convert the ZipOutputStream into InputStream (for example into ZipIntputStream) and download that ZipInputStream. For doing this I use this code: ``` public void downloadZip() { contentType = "application/octet-stream"; filename="myZip.zip"; ByteArrayOutputStream baos = new ByteArrayOutputStream(); byte[] bytes; try { ZipOutputStream zos = new ZipOutputStream(baos); ZipEntry ze; bytes = otherClass.getBytes("File1"); ze = new ZipEntry("File1.pdf"); zos.putNextEntry(ze); zos.write(bytes); zos.closeEntry(); bytes = otherClass.getBytes("File2"); ze = new ZipEntry("File2.pdf"); zos.putNextEntry(ze); zos.write(bytes); zos.closeEntry(); zos.flush(); inputStream = new ZipInputStream(new ByteArrayInputStream(baos.toByteArray())); zos.close(); } catch(Exception e){...} } ``` My action struts.xml ``` <action...> <result name="success" type="stream"> <param name="contentType">${contentType}</param> <param name="inputName">inputStream</param> <param name="contentDisposition">attachment;filename="${filename}"</param> <param name="bufferSize">1024</param> </result> </action> ``` The problem is that the browser shows me a message says to me that the file it's not a valid zip, and its size is 0 bytes. I hope I explained clearly, thanks a lot in advance. Edit: As I have commented, finally I get the solution and it's very similar to leonbloy's reply. Besides return the ByteArrayInputStream I should close the ZipOutputStream before create the ByteArrayInputStream. Here's the result code, maybe it can be useful for other people: ``` ... zos.closeEntry(); zos.close(); inputStream = new ByteArrayInputStream(baos.toByteArray()); } catch(Exception e){...} } ``` Thanks for your help.