Remove %0D from variable in BASH
bash, wget
Solution
You can add `| tr -d '\r'` to your curl pipeline to strip any carriage returns.
Problem
I'm trying this: ``` token=`curl -I --header "X-Auth-User: user@user.com" --header "X-Auth-Key: XXXXXXXXXXXXXXXXXXXXXX" api.server.com | grep -Fi X-Auth-Token | awk -F" " '{ print $2}'` /usr/bin/wget --accept .jpg,.jpeg -p "https://api.server.com/v1/stats/1/graph?callback=jQuery171027000000144289315_1380000003353&mnum=1&res_type=cpu&g_type=6h&graph_type=img&full=1&w=515&h=150&X-Auth-Token=$token" -O "image.jpg" || rm "image.jpg" ``` But my token result is: ``` https://api.server.com/v1/stats/1/graph?callback=jQuery171027000000144289315_1380000003353&mnum=1&res_type=cpu&g_type=6h&graph_type=img&full=1&w=515&h=150&X-Auth-Token=SERVER_018d8100000000001d1b817f7d58a6%0D ``` Instead of: ``` https://api.server.com/v1/stats/1/graph?callback=jQuery171027000000144289315_1380000003353&mnum=1&res_type=cpu&g_type=6h&graph_type=img&full=1&w=515&h=150&X-Auth-Token=SERVER_018d8100000000001d1b817f7d58a6 ``` How to remove %0D (Carriage return)?