Sort multidimensional array based on 2nd element of the subarray
arrays, list, multidimensional-array, python, sorting
Solution
`list.sort`, `sorted` accept optional `key` parameter. `key` function is used to generate comparison key.
>>> sorted(lst, key=lambda x: x[1], reverse=True)
[['I', 219], ['A', 22], ['P', 14], ['V', 13], ['G', 10], ...]
>>> sorted(lst, key=lambda x: -x[1])
[['I', 219], ['A', 22], ['P', 14], ['V', 13], ['G', 10], ...]
>>> import operator
>>> sorted(lst, key=operator.itemgetter(1), reverse=True)
[['I', 219], ['A', 22], ['P', 14], ['V', 13], ['G', 10], ...]
Problem
I have an array like this: ``` [['G', 10], ['A', 22], ['S', 1], ['P', 14], ['V', 13], ['T', 7], ['C', 0], ['I', 219]] ``` I'd like to sort it based on the 2nd element in descending order. An ideal output would be: ``` [['I', 219], ['A', 22], ['P', 14], ... ] ```