Bash: Why is echo adding extra space?

Question

I get: ``` $ echo -e "D"{a,b,c}".jpg
" Da.jpg Db.jpg Dc.jpg ``` Note: The extra spaces before Db and Dc on the 2nd and 3rd line of the output. Why are these there? Thanks, Dan Edit: Since my actual objective had spaces in it (which I should have written originally): ``` echo -e "Name"{,.}" "{-,}"extra"{,so}" 5v5 "{one,two,No\ four}{,!,\!\!}"
" ``` Most solutions here didn't work for me (for loop, xarg, tr). Printf didn't work because of multiple braces expansions that I want to cantesian product. I combined 3 solutions (mletterle's \b, Dennis Williamson's extra space, and Jim Dennis's using far less quotes) to get: ``` echo -e "" \bName{,.}\ {-,}extra{,so}\ 5v5\ {one,two,No\ four}{,\!,\!\!}\n ``` Thanks all who answered! I learned a lot from your responses! Dan

Accepted Answer

The easiest and cleanest solution is to add a backspace to the front of each line:

```
echo -e -n "\bD"{a,b,c}".jpg
"
```

This produces the desired output.

Bash: Why is echo adding extra space?

Solution

Problem