Python nested dictionary comprehension returns empty dictionaries

dictionary, list-comprehension, python

Solution

Something like this:

>>> {k: {8: v[8]} for k, v in data_dict.items() if 8 in v}
{'three': {8: 'h'}}

Problem

I'm using dictionary comprehension to pull out a nested value. I have the following code (as a sample): ``` d = {1: 'a', 2: 'b', 3: 'c'} e = {4: 'd', 5: 'e', 6: 'f'} f = {7: 'g', 8: 'h', 9: 'i'} # stick them together into another dict data_dict = {'one': d, 'two': e, 'three': f} #say we're looking for the key 8 output = {outer_key: {inner_key: inner_value for inner_key, inner_value in outer_value.items() if inner_key == 8} for outer_key, outer_value in data_dict.items()} output = {'one': {}, 'three': {8: 'h'}, 'two': {}} ``` what do I need to do to get JUST 'three' and its value? I don't want to return empty matches. thx

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