Printing the physical address of a C pointer
c, memory
Solution
It's in terms of virtual address space. It's impossible to get a "physical" address in standard C (unless you're on a system which doesn't have virtual memory, of course, in which case it'll always be the physical address) - if it's currently in swap space, for instance, it may not even have one, other than a current location on disk, which wouldn't be very useful to you.
Problem
I can print the address of a pointer by using the following code ``` #include<stdio. int main(){ int *q =(int*) malloc(4); printf("%x\n",q); } ``` When i execute the following code a hexadecimal value is printed. Is it the virtual address or the physical address of variable q on heap? If it is virtual how should i print the other?