How do I check if a char is a vowel?

Question

This Java code is giving me trouble: ``` String word = <Uses an input> int y = 3; char z; do { z = word.charAt(y); if (z!='a' || z!='e' || z!='i' || z!='o' || z!='u')) { for (int i = 0; i==y; i++) { wordT = wordT + word.charAt(i); } break; } } while(true); ``` I want to check if the third letter of word is a non-vowel, and if it is I want it to return the non-vowel and any characters preceding it. If it is a vowel, it checks the next letter in the string, if it's also a vowel then it checks the next one until it finds a non-vowel. Example: word = Jaemeas then wordT must = Jaem Example 2: word=Jaeoimus then wordT must =Jaeoim The problem is with my `if` statement, I can't figure out how to make it check all the vowels in that one line.

Accepted Answer

Your condition is flawed. Think about the simpler version

```
z != 'a' || z != 'e'
```

If `z` is `'a'` then the second half will be true since `z` is not `'e'` (i.e. the whole condition is true), and if `z` is `'e'` then the first half will be true since `z` is not `'a'` (again, whole condition true). Of course, if `z` is neither `'a'` nor `'e'` then both parts will be true. In other words, your condition will never be false!

You likely want `&&`s there instead:

```
z != 'a' && z != 'e' && ...
```

Or perhaps:

```
"aeiou".indexOf(z) < 0
```

How do I check if a char is a vowel?

Solution

Problem