How to click a link whose href has a certain substring in Selenium?

Question

The following is a bunch of links ` name1 name2 // The one that I need name3 name4 ................... ``` I need to click the link whose `href` has substring "long" in it. How can I do this? PS: `driver.findElement(By.partialLinkText("long")).click();` // b/c it chooses by the name

Accepted Answer

I need to click the link whose href has substring "long" in it. How can I do this?

With the beauty of CSS selectors.

your statement would be...

```
driver.findElement(By.cssSelector("a[href*='long']")).click();
```

This means, in english,

Find me any 'a' elements, that have the `href` attribute, and that attribute `contains` 'long'

You can find a useful article about formulating your own selectors for automation effectively, as well as a list of all the other equality operators. `contains`, `starts with`, etc... You can find that at: http://ddavison.io/css/2014/02/18/effective-css-selectors.html

How to click a link whose href has a certain substring in Selenium?

Solution

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