How do I find .index of a multidimensional array

ruby

Solution

a.each_index { |i| j = a[i].index 'S'; p [i, j] if j }

Update: OK, we can return multiple matches. It's probably best to utilize the core API as much as possible, rather than iterate one by one with interpreted Ruby code, so let's add some short-circuit exits and iterative evals to break the row into pieces. This time it's organized as an instance method on Array, and it returns an array of [row,col] subarrays.

a = [ %w{ a b c d },
      %w{ S },
      %w{ S S S x y z },
      %w{ S S S S S S },
      %w{ x y z S },
      %w{ x y S a b },
      %w{ x },
      %w{ } ]

class Array
  def locate2d test
    r = []
    each_index do |i|
      row, j0 = self[i], 0
      while row.include? test
        if j = (row.index test)
          r << [i, j0 + j]
          j  += 1
          j0 += j
          row = row.drop j
        end
      end
    end
    r
  end
end

p a.locate2d 'S'

Problem

Tried web resources and didnt have any luck and my visual quick start guide. If I have my 2d/multidimensional array: ``` array = [['x', 'x',' x','x'], ['x', 'S',' ','x'], ['x', 'x',' x','x']] print array.index('S') it returns nil ``` So then I go and type: ``` array = ['x', 'S',' ','x'] print array.index('S') ``` it returns the value I am looking for 1 My first guess something is being called wrong in the .index() and it needs two arguments one for both row and column? Anyways how do I make .index work for a multidimensional array? This is step one for solving my little maze problem

Original source