Combine enums c++

c++, c++11, enums

Solution

What I've commonly seen is this:

enum OperationType {
    Comparison = 0x100,
    Arithmetic = 0x200
};        

enum ComparisonType
{
    LT = Comparison,     // "<"
    GT,     // ">"
    EQ,     // "=="
    LTEQ,   // "<="
    GTEQ,   // ">="
    NEQ     // "!="
};
enum ArithmeticType
{
    ADD = Arithmetic,    // "+"
    SUB,    // "-"
    MUL,    // "*"
    DIV,    // "/"
    MOD,    // "%"
};

Which gives you a little more flexibility than simple chaining, because now you can add comparisons without disrupting your Arithmetics, and the Arithmetics and Comparisons don't need to know about eachother. It also becomes trivial to get the type of an enum:

constexpr OperationType getOperationType(unsigned value)
{return static_cast<OperationType>(value&0xFF00);}

Problem

In my project, I have several enum declarations alike this one; ``` enum Comparison { LT, // "<" GT, // ">" EQ, // "==" LTEQ, // "<=" GTEQ, // ">=" NEQ // "!=" }; enum Arithmetic {     ADD,    // "+"     SUB,    // "-"     MUL,    // "*"     DIV,    // "/"     MOD,    // "%" }; ``` And I'd like to combine several of these, into a single combined enum, such that; - All elements (from the sub-enums) are present in the combined enum. - All elements have a unique value (obviously). - All elements have consistent value in the combined enum, and the original. Like this: ``` enum Comparison { LT, // "<" GT, // ">" EQ, // "==" LTEQ, // "<=" GTEQ, // ">=" NEQ // "!="     ADD,    // "+"     SUB,    // "-"     MUL,    // "*"     DIV,    // "/"     MOD,    // "%" }; ``` Also what I'd like to be able to do, is to 'cast' the combined enum, to one of the original ones, given the value in the combined enum only (should be trivial assuming the values are consistent). An alternative to enum, is a class based solution, where the classes implement the `operator int()` operator. Note; I do believe the `operator int()` is somehow the way to go.

Original source