sed: replace a line containing a pattern
regex, replace, sed, shell
Solution
You need to match the whole line containing that pattern and then replace. Use it like this:
sed 's/^.*\bpattern\b.*$/Substitution/' file
I also added `\b` for word boundaries so that you only match `pattern` but avoid matching `patterns`.
Explanation: `^.*\bpattern\b.*$` us used to make sure whole line is matched containing pattern. `^` is line start and `$` is line end. `.*` matches 0 or more length text. So `^.*` matches all the text before `pattern` and `.*$` matches all the text after `pattern`.
Using awk you can do:
awk '!/affraid/{print} /affraid/{print "Substitution"}' file
Problem
I saw so much questions about the `sed` command but none match my dude. I want to substitute the entire line which contains a pattern. I think the `sed` command is the best option. I started with this `sed` command but doesn't work ``` sed -i 's/pattern/Substitution/' myfile.txt ``` After that i'm testing with this other command but only substitute the pattern, not the entire line. ``` echo "hello y luego bye" | sed "s|hello|adeu|g" ```