fnmatch and recursive path match with `**`
fnmatch, glob, python
Solution
If you look into fnmatch source code closely, it internally converts the pattern to a regular expression, mapping `*` into `.*` (and not `[^/]*` or similar) and thus does not care anything for directory separators `/` - unlike UNIX shells:
while i < n:
c = pat[i]
i = i+1
if c == '*':
res = res + '.*'
elif c == '?':
res = res + '.'
elif c == '[':
...
Thus
>>> fnmatch.fnmatch('a/b/d/c', 'a/*/c')
True
>>> fnmatch.fnmatch('a/b/d/c', 'a/*************c')
True
Problem
Is there any built-in or straightforward way to match paths recursively with double asterisk, e.g. like zsh does? For example, with ``` path = 'foo/bar/ham/spam/eggs.py' ``` I can use fnmatch to test it with ``` fnmatch(path, 'foo/bar/ham/*/*.py' ``` Although, I would like to be able to do: ``` fnmatch(path, 'foo/**/*.py') ``` I know that fnmatch maps its pattern to regex, so in the words case I can roll my own fnmatch with additional `**` pattern, but maybe there is an easier way