Find element's index in pandas Series
pandas, python
Solution
>>> myseries[myseries == 7]
3 7
dtype: int64
>>> myseries[myseries == 7].index[0]
3
Though I admit that there should be a better way to do that, but this at least avoids iterating and looping through the object and moves it to the C level.
Problem
I know this is a very basic question but for some reason I can't find an answer. How can I get the index of certain element of a Series in python pandas? (first occurrence would suffice) I.e., I'd like something like: ``` import pandas as pd myseries = pd.Series([1,4,0,7,5], index=[0,1,2,3,4]) print myseries.find(7) # should output 3 ``` Certainly, it is possible to define such a method with a loop: ``` def find(s, el): for i in s.index: if s[i] == el: return i return None print find(myseries, 7) ``` but I assume there should be a better way. Is there?