C Unsigned int providing a negative value?
c, int, unsigned
Solution
Printing `%d` will read the integer as a signed decimal number, regardless of its defined type.
To print unsigned numbers, use `%u`.
This happens because of C's way to handle variable arguments. The compiler just pulls values from the stack (typed as `void*` and pointing to the call stack) and `printf` has to figure out what the data contains from the format string you give it to.
This is why you need to supply the format string - C has no way of RTTI or a 'base class' (`Object` in Java, for example) to get a generic or predefined `toString` from.
Problem
I have an unsigned integer but when i print it out using %d there is sometimes a negative value there?