Removing files interactively with find and xargs
rm, shell, xargs
Solution
Can someone explain to me what's exactly is happening,
As the man page for xargs says (under the `-a` option): "If you use this option, stdin remains unchanged when commands are run. Otherwise, stdin is redirected from /dev/null."
Since you're not using the `-a` option, each `rm -i` command that `xargs` is running gets its stdin from /dev/null (i.e. no input is available). When `rm` asks whether to remove a particular file, the answer is effectively "no" because /dev/null gives no reply. `rm` receives an EOF on its input, so it does not remove that file, and goes on to the next file.
and what I can do to get my desired results?
Besides using `find -exec` as unxnut explained, another way to do it is to use the `-o` (or `--open-tty`) option with `xargs`:
find -name '#*#' -print0 | xargs -0 -o rm -i
That's probably the ideal way, because it allows `rm -i` to handle interactive confirmation itself, as designed.
Another way is to use the `-p` (or `--interactive`) option with `xargs`:
find -name '#*#' -print0 | xargs -0 -p rm
With this approach, `xargs` handles the interactive confirmation instead of having `rm` do it. You may also want to use `-n 1`, so that each prompt only asks about one file:
find -name '#*#' -print0 | xargs -0 -p -n 1 rm
The advantage of using `xargs` over `find -exec` is that you can use it with any command that generates the file path arguments, not just with `find`.
Problem
I'm trying to pipe some files from the find command to the interactive remove command, so that I can double check the files I'm removing, but I've run into some trouble. ``` find -name '#*#' -print0 | xargs -0 rm -i ``` I thought the above would work, but instead I just get a string of `"rm: remove regular file ./some/path/#someFile.js#? rm: remove regular file ./another/path/#anotherFile#?..."` Can someone explain to me what's exactly is happening, and what I can do to get my desired results? Thanks.