How to read/write from/to a file using Go
file, go
Solution
Let's make a Go 1-compatible list of all the ways to read and write files in Go.
Because file API has changed recently and most other answers don't work with Go 1. They also miss `bufio` which is important IMHO.
In the following examples I copy a file by reading from it and writing to the destination file.
Start with the basics
package main
import (
"io"
"os"
)
func main() {
// open input file
fi, err := os.Open("input.txt")
if err != nil {
panic(err)
}
// close fi on exit and check for its returned error
defer func() {
if err := fi.Close(); err != nil {
panic(err)
}
}()
// open output file
fo, err := os.Create("output.txt")
if err != nil {
panic(err)
}
// close fo on exit and check for its returned error
defer func() {
if err := fo.Close(); err != nil {
panic(err)
}
}()
// make a buffer to keep chunks that are read
buf := make([]byte, 1024)
for {
// read a chunk
n, err := fi.Read(buf)
if err != nil && err != io.EOF {
panic(err)
}
if n == 0 {
break
}
// write a chunk
if _, err := fo.Write(buf[:n]); err != nil {
panic(err)
}
}
}
Here I used `os.Open` and `os.Create` which are convenient wrappers around `os.OpenFile`. We usually don't need to call `OpenFile` directly.
Notice treating EOF. `Read` tries to fill `buf` on each call, and returns `io.EOF` as error if it reaches end of file in doing so. In this case `buf` will still hold data. Consequent calls to `Read` returns zero as the number of bytes read and same `io.EOF` as error. Any other error will lead to a panic.
Using `bufio`
package main
import (
"bufio"
"io"
"os"
)
func main() {
// open input file
fi, err := os.Open("input.txt")
if err != nil {
panic(err)
}
// close fi on exit and check for its returned error
defer func() {
if err := fi.Close(); err != nil {
panic(err)
}
}()
// make a read buffer
r := bufio.NewReader(fi)
// open output file
fo, err := os.Create("output.txt")
if err != nil {
panic(err)
}
// close fo on exit and check for its returned error
defer func() {
if err := fo.Close(); err != nil {
panic(err)
}
}()
// make a write buffer
w := bufio.NewWriter(fo)
// make a buffer to keep chunks that are read
buf := make([]byte, 1024)
for {
// read a chunk
n, err := r.Read(buf)
if err != nil && err != io.EOF {
panic(err)
}
if n == 0 {
break
}
// write a chunk
if _, err := w.Write(buf[:n]); err != nil {
panic(err)
}
}
if err = w.Flush(); err != nil {
panic(err)
}
}
`bufio` is just acting as a buffer here, because we don't have much to do with data. In most other situations (specially with text files) `bufio` is very useful by giving us a nice API for reading and writing easily and flexibly, while it handles buffering behind the scenes.
Note: The following code is for older Go versions (Go 1.15 and before). Things have changed (`ioutil` is deprecated since Go 1.16). For the new way, take a look at this answer.
Using `ioutil`
package main
import (
"io/ioutil"
)
func main() {
// read the whole file at once
b, err := ioutil.ReadFile("input.txt")
if err != nil {
panic(err)
}
// write the whole body at once
err = ioutil.WriteFile("output.txt", b, 0644)
if err != nil {
panic(err)
}
}
Easy as pie! But use it only if you're sure you're not dealing with big files.
Problem
I've been trying to learn Go on my own, but I've been stumped on trying read from and write to ordinary files. I can get as far as `inFile, _ := os.Open(INFILE, 0, 0)`, but actually getting the content of the file doesn't make sense, because the read function takes a `[]byte` as a parameter. ``` func (file *File) Read(b []byte) (n int, err Error) ```