Bash Scripting " [!: not found " errors, and how to write an or statement

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EDIT: Here is my updated code: ``` #!/bin/sh files=`ls` if [ $# -ne 1 -o -f $1 ] then echo "Usage: $0 <directory>" exit 1 fi if [ ! -e $1 ] then echo "$1 not found" exit 1 elif [ -d $1 ] then cd $1 for f in $files do if [ ! -d "$f" ] then if [ ! -s "$f" ] then rm -r "$f" echo "File: $f was removed." else continue fi fi done echo "Name		Links		Owner		Date" for f in $files do find "$f" -type f -printf "%f		 %n		 %u	 %TH %Tb %TY
" done exit 0 fi ``` I fixed all of the spacing issues, changed #!bin/sh to #/bin/bash, and added quotes to "$f". However I'm still getting lots of errors. ava@kosh:~/test$ ./delDir d1 rm: cannot remove `d1': No such file or directory File: d1 was removed. rm: cannot remove`delDir': No such file or directory File: delDir was removed. rm: cannot remove `delDir2': No such file or directory File: delDir2 was removed. rm: cannot remove`e1': No such file or directory File: e1 was removed. rm: cannot remove `e2': No such file or directory File: e2 was remov…

Accepted Answer

Another issue is that at the start of the script you do

```
files = `ls`
```

but then you cd to a different directory and try to loop round $files deleting them - of course this will not work since you have changed directories.

move the ls line to after you have changed directory.

Bash Scripting " [!: not found " errors, and how to write an or statement

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