Find list index of list items within other list items
list-comprehension, python, python-3.x
Solution
You are looking for the `any()` function here:
matching = [i for i, x in enumerate(my_list) if any(thing in x for thing in things_to_find)]
Demo:
>>> my_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
>>> things_to_find = ['abc', 'def']
>>> [i for i, x in enumerate(my_list) if any(thing in x for thing in things_to_find)]
[0, 1, 3]
Problem
I have a list of long strings and I'd like to get the indexes of the list elements that match a substring of strings in another list. Checking if a list item contains a a single string inside a list is easy to do with list comprehensions, like this question: ``` my_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456'] thing_to_find = "abc" matching = [i for i, x in enumerate(my_list) if thing_to_find in x] ``` However, I'd like to check not only if `"abc"` is in `x`, but if any strings in another list are in the list, like so: ``` my_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456'] things_to_find = ['abc', 'def'] ``` This obviously doesn't work (but it would be really cool if it did): ``` matching = [i for i, x in enumerate(my_list) if things_to_find in x] ``` I can find the list indexes if I run commands individually, but it's tedious and horrible: ``` print([i for i, x in enumerate(my_list) if 'abc' in x]) # [0, 3] print([i for i, x in enumerate(my_list) if 'def' in x]) # [1] ``` What's the best way to find the indexes of all instances where elements from one list are found in another list?