Templated enum types based on template parameters
c++, enums, templates
Solution
You need to tell the compiler that `T::B` is a type, because it is a dependent name, and is assumed to be a non-type by default.
template<typename T>
static void Foo(T t, typename T::B b) {}
// ^^^^^^^^
You should also make the enum public. This code sample works:
class A {
public:
enum B {x, y, z};
};
template<typename T>
static void Foo(T t, typename T::B b) {}
int main()
{
Foo(A(), A::x); // OK
}
For an in-depth explanation, see Where and why do I have to put the “template” and “typename” keywords?:
Problem
I was wondering how to do this: Say I have a class A, with enum B inside it ``` class A { enum B { }; }; ``` And I'd like to create a function that takes A as a template and then assumes A has an enum B type and receives its val as a parameter? I tried something like: ``` template<typename T> static void Foo(T t, T::B b) {} ``` But that didn't work.. anyone has an idea? Thanks.